玫瑰花的实现
javascript
2016-08-06
var b = document.body;
var c = document.getElementsByTagName('canvas')[0];
var a = c.getContext('2d');
var canvas = document.getElementsByTagName('canvas')[0];
var ctx = canvas.getContext('2d');
document.body.clientWidth;
with (m = Math) C = cos, S = sin, P = pow, R = random;
c.width = c.height = f = 500;
h =- 250;
function p(a, b, c)
{
    if (c > 60)
    {
        return [S(a * 7) * (13 + 5  / (.2 + P(b * 4, 4))) - S(b) * 50, b * f + 50, 625 + C(a * 7) * (13 + 5  / (.2 + P(b * 4,
        4))) + b * 400, a * 1 - b  / 2, a];
    }
    A = a * 2 - 1;
    B = b * 2 - 1;
    if (A * A + B * B < 1)
    {
        if (c > 37)
        {
            n = (j = c & 1) ? 6 : 4;
            o = .5 / (a + .01) + C(b * 125) * 3 - a * 300;
            w = b * h;
            return [o * C(n) + w * S(n) + j * 610 - 390, o * S(n) - w * C(n) + 550 - j * 350, 1180 + C(B + A) * 99 - j * 300,
            .4 - a * .1 + P(1 - B * B, - h * 6) * .15 - a * b * .4 + C(a + b) / 5 + P(C((o * (a + 1) + (B > 0 ? w :- w)) / 25),
            30) * .1 * (1 - B * B), o / 1e3 + .7 - o * w * 3e - 6]
        }
        if (c > 32)
        {
            c = c * 1.16 - .15;
            o = a * 45 - 20;
            w = b * b * h;
            z = o * S(c) + w * C(c) + 620;
            return [o * C(c) - w * S(c), 28 + C(B * .5) * 99 - b * b * b * 60 - z / 2 - h, z, (b * b * .3 + P((1 - (A * A)),
            7) * .15 + .3) * b, b * .7]
        }
        o = A * (2 - b) * (80 - c * 2);
        w = 99 - C(A) * 120 - C(b) * (-h - c * 4.9) + C(P(1 - b, 7)) * 50 + c * 2;
        z = o * S(c) + w * C(c) + 700;
        return [o * C(c) - w * S(c), B * 99 - C(P(b, 7)) * 50 - c / 3 - z / 1.35 + 450, z, (1 - b / 1.2) * .9 + a * .1,
        P((1 - b), 20) / 4 + .05]
    }
}
var draw = setInterval('for(i=0;i<1e4;i++)if(s=p(R(),R(),i%46/.74)){z=s[2];x=~~(s[0]*f/z-h);y=~~(s[1]*f/z-h);if(!m[q=y*f+x]|m[q]>z)m[q]=z,a.fillStyle="rgb("+~(s[3]*h)+","+~(s[4]*h)+","+~(s[3]*s[3]*-80)+")",a.fillRect(x,y,1,1)}',
0);
var demo = document.getElementById('demo');
function redraw()
{
    /*
        var d_c = document.createElement("canvas");
        d_c.setAttribute("id","c");
        d_c.setAttribute("width","520");
        d_c.setAttribute("height","500");
        demo.appendChild(d_c);
        */
    draw = setInterval('for(i=0;i<1e4;i++)if(s=p(R(),R(),i%46/.74)){z=s[2];x=~~(s[0]*f/z-h);y=~~(s[1]*f/z-h);if(!m[q=y*f+x]|m[q]>z)m[q]=z,a.fillStyle="rgb("+~(s[3]*h)+","+~(s[4]*h)+","+~(s[3]*s[3]*-80)+")",a.fillRect(x,y,1,1)}',
    0);
    //alert(d_c);
}
function clear_canvas()
{
    ctx.clearRect(0, 0, 520, 500);
    //canvas.parentNode.removeChild(canvas);   //删除
}
function stop_draw(obj)
{
    clearInterval(obj);
}




var b = document.body;
var c = document.getElementsByTagName('canvas')[0];
var a = c.getContext('2d');
var canvas = document.getElementsByTagName('canvas')[0];
var ctx = canvas.getContext('2d');
document.body.clientWidth;
with (m = Math) C = cos, S = sin, P = pow, R = random;
c.width = c.height = f = 500;
h =- 250;
function p(a, b, c)
{
    if (c > 60)
    {
        return [S(a * 7) * (13 + 5  / (.2 + P(b * 4, 4))) - S(b) * 50, b * f + 50, 625 + C(a * 7) * (13 + 5  / (.2 + P(b * 4,
        4))) + b * 400, a * 1 - b  / 2, a];
    }
    A = a * 2 - 1;
    B = b * 2 - 1;
    if (A * A + B * B < 1)
    {
        if (c > 37)
        {
            n = (j = c & 1) ? 6 : 4;
            o = .5 / (a + .01) + C(b * 125) * 3 - a * 300;
            w = b * h;
            return [o * C(n) + w * S(n) + j * 610 - 390, o * S(n) - w * C(n) + 550 - j * 350, 1180 + C(B + A) * 99 - j * 300,
            .4 - a * .1 + P(1 - B * B, - h * 6) * .15 - a * b * .4 + C(a + b) / 5 + P(C((o * (a + 1) + (B > 0 ? w :- w)) / 25),
            30) * .1 * (1 - B * B), o / 1e3 + .7 - o * w * 3e - 6]
        }
        if (c > 32)
        {
            c = c * 1.16 - .15;
            o = a * 45 - 20;
            w = b * b * h;
            z = o * S(c) + w * C(c) + 620;
            return [o * C(c) - w * S(c), 28 + C(B * .5) * 99 - b * b * b * 60 - z / 2 - h, z, (b * b * .3 + P((1 - (A * A)),
            7) * .15 + .3) * b, b * .7]
        }
        o = A * (2 - b) * (80 - c * 2);
        w = 99 - C(A) * 120 - C(b) * (-h - c * 4.9) + C(P(1 - b, 7)) * 50 + c * 2;
        z = o * S(c) + w * C(c) + 700;
        return [o * C(c) - w * S(c), B * 99 - C(P(b, 7)) * 50 - c / 3 - z / 1.35 + 450, z, (1 - b / 1.2) * .9 + a * .1,
        P((1 - b), 20) / 4 + .05]
    }
}
var draw = setInterval('for(i=0;i<1e4;i++)if(s=p(R(),R(),i%46/.74)){z=s[2];x=~~(s[0]*f/z-h);y=~~(s[1]*f/z-h);if(!m[q=y*f+x]|m[q]>z)m[q]=z,a.fillStyle="rgb("+~(s[3]*h)+","+~(s[4]*h)+","+~(s[3]*s[3]*-80)+")",a.fillRect(x,y,1,1)}',
0);
var demo = document.getElementById('demo');
function redraw()
{
    /*
        var d_c = document.createElement("canvas");
        d_c.setAttribute("id","c");
        d_c.setAttribute("width","520");
        d_c.setAttribute("height","500");
        demo.appendChild(d_c);
        */
    draw = setInterval('for(i=0;i<1e4;i++)if(s=p(R(),R(),i%46/.74)){z=s[2];x=~~(s[0]*f/z-h);y=~~(s[1]*f/z-h);if(!m[q=y*f+x]|m[q]>z)m[q]=z,a.fillStyle="rgb("+~(s[3]*h)+","+~(s[4]*h)+","+~(s[3]*s[3]*-80)+")",a.fillRect(x,y,1,1)}',
    0);
    //alert(d_c);
}
function clear_canvas()
{
    ctx.clearRect(0, 0, 520, 500);
    //canvas.parentNode.removeChild(canvas);   //删除
}
function stop_draw(obj)
{
    clearInterval(obj);
}

这里用了多个不同的形状图来组成这朵代码玫瑰。共使用了31个形状:24个花瓣,4个萼片, 2个叶子和1根花茎,其中每一个形状图都用代码进行描绘。表面采样方法是创建三维图形非 常著名的、最古老的方法之一,但这种把蒙特卡罗、z-buffer加入到表面采样中的方法并不 常见。对于现实生活场景的制作,这也许算不上很有创意,但它简易的代码实现和很小的体 积仍令人满意。

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